The Supreme Court has ordered former BNP minister Barrister Nazmul Huda to surrender to the lower court in a bribery case.
Barrister Nazmul Huda filed a petition asking the apex court’s permission to allow him to file an appeal against a High Court verdict without surrendering to the lower court.
A five-member bench of the Appellate Division Court headed by acting chief Justice Md Abdul Wahhab Miah passed the order on Sunday, rejecting a petition filed by the BNP leader.
Advocate Khurshid Alam Khan, lawyer of the Anti-Corruption Commission’s lawyer, said Nazmul Huda must surrender to the trial court in the bribery case involving Tk 2.4 crore following the Supreme Court order.
On November 8, 2017, the High Court reduced the jail term of former BNP communication minister Nazmul Huda to four years from seven years in the case filed during the regime of military-backed caretaker government.
The ACC on March 21, 2007 filed the case with Dhanmondi Police Station in the city bringing allegation that Nazmul Huda took Tk 2.40 crore as bribe from a businessman, Mir Zahir Hossain,on different occasions, in exchange for awarding him five government contracts for construction works, including road repairs worth about Tk 30 crore.